C++ Program To Check Whether The User Entered Integer Is Palindrome Or Not.

This Post Contains A C++ Program To Check Whether The User Entered Integer Is Palindrome With Correct Source Code, Algorithm & Output. This Program Is Written, Compiled & Executed At TurboC/C++3.0 Compiler & Will Help You To Understand The Concept Of 'While-Loop' & 'If...else' From C++ Language. It Is A Well-Structured Program With Proper Comments Which Provides Step-By-Step Description Of Various Features Of The Language In A Simple & Easy-To-Understand Way.



# Note : You Can Simply Copy-Paste The Following Program Or Code Into Compiler For Direct Result.


C++ Program To Check Whether The User Entered Integer Is Palindrome Or Not.

/* Declaration Of Header Files */
#include<iostream.h>
#include<conio.h>

/* Start Of Main Program */
void main()
{

/* Declaration Of Variables */
int Num, Rem=0, Quo=0, temp=0;
clrscr();

/* Asking For The Input From User */
cout<<" \n Please Enter A Number : ";
cin>>Num;

/* Source Code For Checking Integer As Palindrome */
Quo=Num;
while(Quo!=0)
{
   Rem = Quo % 10;
   temp = (temp*10) + Rem;
   Quo = Quo / 10;
}
if(Num==temp)
{
cout<<" \n The Number "<<Num<<" Is Palindrome ";
}
else
{
cout<<" \n The Number "<<Num<<" Is Not Palindrome ";
}
getch();
}
/* End Of Main Program */

Output :

Please Enter A Number : 11

The Number 11 Is Palindrome

Please Enter A Number : 21

The Number 21 Is Not Palindrome